Practice MCQ Questions and Answer on Decimal Fraction

91.

Solve 1599 ÷ 39.99 + $$\frac{4}{5}$$ × 2449 - 120.05 = ?

• (A) 1880
• (B) 1940
• (C) 1680
• (D) 1980

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 Given = 1599 ÷ 39.99 + $$\frac{4}{5}$$ × 2449 - 120.05 = 1600 ÷ 40 + $$\frac{4}{5}$$ × 2450 - 120 = 1600 ÷ 40 + 1960 - 120 = 40 + 1960 - 120 = 1880

92.

Solve : $$2\frac{2}{9}$$ + $$4\frac{1}{18}$$ - $$1\frac{1}{2}$$ = ?

• (A) $$4\frac{5}{9}$$
• (B) $$4\frac{7}{9}$$
• (C) $$5\frac{8}{9}$$
• (D) $$6\frac{1}{2}$$

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 $$2\frac{2}{9}$$ + $$4\frac{1}{18}$$ - $$1\frac{1}{2}$$ = ? Let the missing number be x x = $$\frac{20}{9}$$ + $$\frac{73}{18}$$ - $$\frac{3}{2}$$ L.C.M. of 9, 18 and 2 is 18 x = $$\frac{40 + 73 - 27}{18}$$ x = $$\frac{86}{18}$$ x = $$\frac{43}{9}$$ x = $$4\frac{7}{9}$$

93.

Solve : 1576 ÷ 45.02 + 23.99 × $$\sqrt {255} $$  = ?

• (A) 340
• (B) 420
• (C) 380
• (D) 460

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 Given expression : = 1576 ÷ 45.02 + 23.99 × $$\sqrt {255} $$ = 1575 ÷ 45 + 24 × $$\sqrt {256} $$ = 35 + 24 × 16 = 35 + 384 = 419 $$ \approx $$ 420

94.

Solve : $$\frac{17292}{33}$$  ÷ 8 = ?

• (A) 23.5
• (B) 53.5
• (C) 65.5
• (D) 33.5

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 = $$\frac{17292}{33}$$ × $$\frac{1}{8}$$ = $$\frac{17292}{33 × 8}$$ = 65.5

95.

6425 ÷ 125 × 8 = ?

• (A) 41.12
• (B) 64.25
• (C) 411.2
• (D) 421.25

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 Given expression : 51.4 × 8 = 411.2

96.

555.05 + 55.5 + 5.55 + 5 + 0.55 = ?

• (A) 621.65
• (B) 634.85
• (C) 647.35
• (D) 655.75

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97.

The rational number for recurring decimal 0.125125.... is:

• (A) $$\frac{{63}}{{487}}$$
• (B) $$\frac{{119}}{{993}}$$
• (C) $$\frac{{125}}{{999}}$$
• (D) None of these

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 $$0.125125... = 0.\overline {125} = \frac{{125}}{{999}}$$

98.

Solve this : $$\frac{1.6 × 3.2}{0.08}$$  = ?

• (A) 0.8
• (B) 6.4
• (C) 8
• (D) 64

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 Given expression : = $$\frac{16 × 32}{8}$$ = 16 × 4 = 64

99.

Which of the following fractions lies between $$\frac{2}{3}$$ and $$\frac{3}{5}$$ = ?

• (A) $$\frac{2}{5}$$
• (B) $$\frac{1}{3}$$
• (C) $$\frac{1}{15}$$
• (D) $$\frac{31}{50}$$

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 $$\eqalign{ & \frac{2}{3} = 0.666 \cr & \frac{3}{5} = 0.6 \cr & \frac{2}{5} = 0.4 \cr & \frac{1}{3} = 0.333 \cr & \frac{1}{{15}} = 0.066 \cr & \frac{{31}}{{50}} = 0.62 \cr} $$ Clearly, 0.62 lies between 0.6 and 0.666 So, $$\frac{31}{50}$$ lies between $$\frac{2}{3}$$ and $$\frac{3}{5}$$

100.

The arrangement of rational numbers, $$\frac{- 7}{10}$$, $$\frac{5}{- 8}$$, $$\frac{2}{- 3}$$  in ascending order is :

• (A) $$\frac{2}{{ - 3}},\frac{5}{{ - 8}},\frac{{ - 7}}{{10}}$$
• (B) $$\frac{5}{{ - 8}},\frac{{ - 7}}{{10}},\frac{2}{{ - 3}}$$
• (C) $$\frac{{ - 7}}{{10}},\frac{5}{{ - 8}},\frac{2}{{ - 3}}$$
• (D) $$\frac{{ - 7}}{{10}},\frac{2}{{ - 3}},\frac{5}{{ - 8}}$$

Show Answer

 $$\frac{- 7}{10}$$ = - 0.7 $$\frac{5}{- 8}$$ = - $$\frac{5}{8}$$ = - 0.625, $$\frac{2}{- 3}$$ = - $$\frac{2}{3}$$ = - 0.66 Since, -0.7 -0.66 -0.625 So, $$\frac{- 7}{10}$$ $$\frac{2}{- 3}$$ $$\frac{5}{- 8}$$