Practice MCQ Questions and Answer on Percentage

21.

One third of a number is 96. What will 67% of that number be ?

(A) 192.96
(B) 181.44
(C) 169.92
(D) 204.48

Solution: Let the number = x ⇒ $\frac{1}{3}$ × x = 96 ⇒ x = 288 ⇒ Required answer : = $\frac{67}{100}$ × 288 = 192.96

22.

If 80% of A = 50% of B and B = x% of A, then the value of x is :

(A) 400
(B) 300
(C) 160
(D) 150

Solution: 80% of A = 50% of B ⇒ $\frac{80}{100}$ A = $\frac{50}{100}$ B ⇒ 8A = 5B ⇒ A = $\frac{5}{8}$ B Put value of A in given equation, B = x% of A ⇒ B = $\frac{x}{100}$ × $\frac{5}{8}$ B ⇒ x = $\frac{100 \times 8}{5}$ ⇒ x = 160

23.

50 minutes is what percentage of a day (approx.)-

(A) 3.5%
(B) 4%
(C) 5%
(D) 6%

24.

If 60% of A's income is equal to 75% of B's income, then B's income is equal to x% of A's income. The value of x is :

(A) 70
(B) 60
(C) 80
(D) 90

Solution: According to the question, ⇒ 60 × $\frac{A}{100}$ = 75 × $\frac{B}{100}$ ⇒ 4A = 5B ⇒ B = $\frac{4}{5}$ A ⇒ A × $\frac{x}{100}$ = B (given) ⇒ A × $\frac{x}{100}$ = $\frac{4}{5}$ A ⇒ x = 80

25.

If x, y, z are three positive integers such that x is greater then y and y is greater than z, then which of the following is definitely true ?

(A) x% of y is greater than y% of z
(B) y% of x is greater than z% of y
(C) z% of x is greater than y% of z
(D) All of these

Solution: (a) x% of y = $\frac{x y}{100}$ and y of z = $\frac{y z}{100}$ x > y, y z ⇒ xy > yz ⇒ $\frac{x y}{100}$ > $\frac{y z}{100}$ ⇒ x% of y > y% of z (b) y% of x = $\frac{x y}{100}$ and z% of y = $\frac{y z}{100}$ As proved above, y% of x > z% of y (c) z% of x = $\frac{x y}{100}$ and y% of z = $\frac{y z}{100}$ x > y ⇒ xz > yz ⇒ $\frac{x z}{100}$ > $\frac{y z}{100}$ ⇒ z% of x > y% of z

26.

In the Science City, Kolkata the rate of the ticket is increased by 50% to increased the revenue but simultaneously 20% of the visitor decreased. What is percentage change in the revenue. if it is known that the Science city collects one revenue only from the visitors and it has no other financial supports:

(A) +20%
(B) -25%
(C) +30%
(D) -30%

27.

In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:

(A) 2700
(B) 2900
(C) 3000
(D) 3100

Solution: Number of valid votes = 80% of 7500 = 6000 ∴ Valid votes polled by other candidate = 45% of 6000 = $\frac{45}{100} \times 6000$ = 2700

28.

Due to fall of 10% in the rate of sugar, 500 gm more sugar can be purchased for Rs. 140. Find the original rate?

(A) Rs. 31.11
(B) Rs. 29.22
(C) Rs. 33.11
(D) Rs. 32.22

Solution: Money spent originally = Rs. 140 Less Money to be spent now = 10% of 140 = Rs. 14 Rs. 14 now yield 500 gm sugar So, Present rate of sugar = Rs. 28 per kg. If the present value is Rs. 90, the original value = Rs. 100 If the present value is Rs. 28 the original value $= Rs . \frac{100}{90} \times 28 = Rs . 31.11$

29.

A sales executive gets 20% bonus of the total sales value and 10% commission besides the bonus on the net profit after charging such commission. If the total sales value be Rs. 10 lakh per annum and the total profit of the company be Rs. 1.32 lakh, then his total earning per annum will be, given that he is not entitled to receive any fixed salary from the company :

(A) 2.3 lakh
(B) 2.32 lakh
(C) 2.12 lakh
(D) 3.2 lakh

Solution: $\begin{aligned} His bonus, \\ = \frac{20 \times 1000000}{100} \\ = 2 lakh \\ Total profit = Net profit + \frac{10 \times net profit}{100} \\ 1.32 lakh = Net profit \times [1 + \frac{10}{100}] \\ Net profit = \frac{132000}{1.1} = 120000 \\ Commission, \\ = (Total profit - Net profit) \\ = 132000 - 120000 \\ = 12000 \\ Hence, his total earnings \\ = 2 lakh + 12000 \\ = R s . 212000 \end{aligned}$

30.

In a survey of a city, it was found that 90 percent of the people in the city own a refrigerator and 15 percent own a washing machine. If everybody owns at least one appliance, what percentage owns both ?

(A) 5 percent
(B) 8 percent
(C) 10 percent
(D) None of these

Solution: $\begin{aligned} n (A) = 90 \\ n (B) = 15 \\ n (A \cup B) = 100 \\ So, \\ n (A \cap B) \\ = n (A) + n (B) - n (A \cup B) \\ = 90 + 15 - 100 \\ = 5 \end{aligned}$ ∴ Percentage of people who own both = 5%

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Practice MCQ Questions and Answer on Percentage

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