Practice MCQ Questions and Answer on Percentage

21.

The value of a machine is Rs. 6250. It decreases by 10% during the first year, 20% during the second year and 30% during the third year, What will be the value of the machine after 3 years ?

(A) Rs. 2650
(B) Rs. 3050
(C) Rs. 3150
(D) Rs. 3510

Solution: Current value of machine $\begin{aligned} = 6250 \times \frac{90}{100} \times \frac{80}{100} \times \frac{70}{100} \\ = Rs . 3150 \end{aligned}$

22.

One third of a number is 96. What will 67% of that number be ?

(A) 192.96
(B) 181.44
(C) 169.92
(D) 204.48

Solution: Let the number = x ⇒ $\frac{1}{3}$ × x = 96 ⇒ x = 288 ⇒ Required answer : = $\frac{67}{100}$ × 288 = 192.96

23.

If the price of a book is first decreased by 25% and then increased by 20%, then the net charges in the price will be :

(A) No change
(B) 5% increase
(C) 5% decrease
(D) 10% decrease

Solution: Let the original price be Rs. 100 New final price : = 120% of (75% of Rs. 100) = Rs. $(\frac{120}{100} \times \frac{75}{100} \times 100)$ = Rs. 90 ∴ Decrease = 10%

24.

A customer asks for the production of x number of goods. The company produces y number of goods daily. Out of which z% are units for sale. The order will be completed in :

(A) $\frac{x}{100 y \times (1 - z)} days$
(B) $\frac{100 y z}{x} days$
(C) $\frac{100 x}{(100 - z) y} days$
(D) $\frac{100}{y \times (z - 1)} days$

Solution: $\begin{aligned} Daily supply, \\ = (100 - z) % of y \\ = \frac{(100 - z) y}{100} \\ Thus, required number of days \\ = \frac{100 x}{(100 - z) y} \end{aligned}$

25.

Nagaraj could save 10% of his income. But 2 years later, when his income increased by 20%, he could save the same amount only as before. By how much percentage has his expenditure increased ?

(A) $22 \frac{2}{9} %$
(B) $23 \frac{1}{3} %$
(C) $24 \frac{2}{9} %$
(D) $25 \frac{2}{9} %$

Solution: Let, his income be = Rs. 100 Saving = Rs. 10 Expenditure = Rs. 90 Increased income = Rs. 120 Increased expenditure = Rs. 110 Increased in expenditure : $\begin{aligned} = \frac{110 - 90}{90} \times 100 \\ = \frac{200}{9} \\ = 22 \frac{2}{9} % \end{aligned}$

26.

If 35% of a number is 175, then what percent of 175 is that number ?

(A) 35%
(B) 65%
(C) 280%
(D) None of these

Solution: Let the number be x Then, 35% of x = 175 ⇔ $\frac{35}{100}$ × x = 175 ⇔ $\frac{175 \times 100}{35}$ = 500 Now, let y% of 175 = 500 Then, $\frac{y}{100}$ × 175 = 500 ⇔ y = $\frac{500 \times 100}{175}$ ⇔ y = $\frac{2000}{7}$ ⇔ y = $285 \frac{5}{7}$

27.

What is the percentage change in the result when we add 50 to a certain number x, instead of subtracting 50 from the same number x?

(A) 50%
(B) 75%
(C) 100%
(D) 300%

Solution: Answer & Solution Answer: Option E Solution: If we take different values of x then, Let x = 150, then error% $\begin{aligned} = \frac{\frac{200 - 100}{100}}{100} \\ = 100 % \end{aligned}$ Again if x = 100, then error% $\begin{aligned} = \frac{(150 - 50) \times 100}{100} \\ = 200 % \end{aligned}$ If we take different value of x, we get different answer so we can't determine it.

28.

What is to be added to 15% of 180 so that the sum is equal to 20% of 360?

(A) 45
(B) 40
(C) 60
(D) 50

Solution: $\begin{aligned} Let be the number is x \\ 180 \times \frac{15}{100} + x = \frac{360 \times 20}{100} \\ 27 + x = 72 \\ x = 72 - 27 \\ x = 45 \end{aligned}$

29.

Solve : 105.27% of 1200.11 + 11.80% of 2360.85 = 21.99% of (?) + 1420.99

(A) 500
(B) 240
(C) 310
(D) 550

Solution: 105.27% of 1200.11 + 11.80% of 2360.85 = 21.99% of (?) + 1420.99 ⇒ 105% of 1200 + 12% of 2360 = 22% of (?) + 1421 ⇒ $\frac{105 \times 1200}{100} + \frac{12 \times 2360}{100} =$ $\frac{22 \times (?)}{100}$ $+ 1421$ $\Rightarrow \frac{22 \times (?)}{100} = 1260 + 283.30$ $- 1421$ $\begin{aligned} \Rightarrow \frac{22 \times (?)}{100} = 1543 - 1421 \\ \Rightarrow \frac{22 \times (?)}{100} = 122 \\ ∴ (?) = \frac{122 \times 100}{22} \\ \Rightarrow (?) = \frac{122 \times 50}{11} \\ \Rightarrow (?) = 554.5 (a p p r o x i m a t e 550) \end{aligned}$

30.

In a school, there are 100 students. 60% of the students are boys, 40% of whom play hockey and the girls don't play hockey, 75% of girls play badminton. There are only two games to be played. The number of student who don't play any game is:

(A) 10%
(B) 20%
(C) 36%
(D) 46%

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Practice MCQ Questions and Answer on Percentage

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