Practice MCQ Questions and Answer on Speed Time and Distance

41.

A train travels the distance between stations P and Q at a speed of 126 km/h, while in the opposite direction it comes back at 90 km/h. Another train travels the same distance at the average speed of the first train. The time taken by the second train to travel 525 km is:

(A) 5 hours
(B) 4 hours
(C) 5 hours 20 minutes
(D) 4 hours 20 minutes

Solution: $\begin{aligned} Average speed = \frac{2 \times 90 \times 126}{216} \\ = \frac{2 \times 5 \times 126}{12} \\ = 105 km/h \\ Time = \frac{525}{105} = 5 hours \end{aligned}$

42.

A train covers a distance of $193 \frac{1}{3}$ km in $4 \frac{1}{4}$ hours with one stoppage of 10 minutes, two of 5 minutes and one of 3 minutes on the way. The average speed of the train is :

(A) 48 km/hr
(B) 50 km/hr
(C) 55 km/hr
(D) 60 km/hr

Solution: Actual time taken for the journey : = 4 hrs 15 min - (10 + 2 × 5 + 3) min = 4 hrs 15 min - 23 min = 3 hrs 52 min = $3 \frac{26}{30}$ hrs = $\frac{116}{30}$ hrs ∴ Average speed : $\begin{aligned} = (\frac{580}{3} \times \frac{30}{116}) km/hr \\ = 50 km/hr \end{aligned}$

43.

A train passes two persons walking in the same direction at a speed of 3 kmph and 5 kmph respectively in 10 seconds and 11 seconds respectively. The speed of the train is

(A) 28 kmph
(B) 27 kmph
(C) 25 kmph
(D) 24 kmph

Solution: 1st method: Let the speed of the train be S. And length of the train be x. When a train crosses a man, its travels its own distance. $\begin{aligned} According to question; \\ \frac{x}{(s - 3) \times \frac{5}{18}} = 10 \\ or, 18 x = 50 \times s - 150. . . . . (i) \\ and \\ \frac{x}{(x - 5) \times \frac{5}{18}} = 11 \\ 18 x = 55 \times s - 275. . . . . . (ii) \\ Equating equation (i) and (ii) \\ 50 \times s - 150 = 55 \times s - 275 \\ or, 5 \times s = 125 \\ or, s = 25 kmph \end{aligned}$

44.

Raj and Prem walk in opposite direction at the rate 3 km/hr and 2 km per hour respectively. How far will they be from each other after 2 hrs ?

(A) 8 km
(B) 10 km
(C) 2 km
(D) 61 km

45.

The distance between the places H and O is D units. The average speed that gets a person from H to O in a stipulated time is S units. He takes 20 minutes more time than usual if he travels at 60 km/h, and reaches 44 minutes early if he travels at 75 km/h. The sum of the numerical values of D and S is:

(A) 358
(B) 384
(C) 376
(D) 344

Solution: Let right time for the train to cover its journey (in minutes) be $t$ hours, then As we know, Distance = Speed × Time According to the question, $\begin{aligned} 60 \times (t + \frac{20}{60}) = 75 \times (t - \frac{44}{60}) \\ \Rightarrow 4 (t + \frac{1}{3}) = 5 (t - \frac{11}{15}) \\ \Rightarrow 4 t + \frac{4}{3} = 5 t - \frac{11}{3} \\ \Rightarrow 5 t - 4 t = \frac{11}{3} + \frac{4}{3} \\ \Rightarrow t = \frac{11 + 4}{3} \\ \Rightarrow t = 5 hours \\ Distance (D) = 60 \times (5 + \frac{20}{60}) \\ \Rightarrow D = 60 \times (5 + \frac{1}{3}) \\ \Rightarrow D = 60 \times \frac{16}{3} \\ \Rightarrow D = 320 km \end{aligned}$ Distance between H and O is 320 km Average speed (S) = $\frac{320}{5}$ = 64 km/hr ∴ Sum of numerical value of D and S = 320 + 64 = 384

46.

If a train with a speed of 60 km/hr. crosses a pole in 30 seconds. The length of the train (in metres) is :

(A) 1000 metres
(B) 900 metres
(C) 750 metres
(D) 500 metres

Solution: The length of pole is considered as negligible i.e., = 0 i.e., when a train crosses the pole, it covers the distance equal to the length of train So, the time will be taken by the train = 30 sec And speed = 60 km/hr Then the length of the train : = 60 kmh × 30 sec = 60 × $\frac{5}{18}$ × 30 metres = 10 × $\frac{5}{3}$ × 30 = 500 metres

47.

Prasad goes 96 kilometres on a bike at a speed of 16 km/h, 124 kilometres at 31 km/h in a car, and 105 kilometres at 7 km/h in a horse cart. Find his average speed for the entire distance travelled.

(A) 16 km/h
(B) 13 km/h
(C) 17 km/h
(D) 11 km/h

Solution: $\begin{aligned} Average speed = \frac{96 + 124 + 105}{\frac{96}{16} + \frac{124}{31} + \frac{105}{7}} \\ = \frac{325}{6 + 4 + 15} \\ = \frac{325}{25} \\ = 13 kmph \end{aligned}$

48.

A covered a distance of 240 km at a certain speed. Had his speed been 8 km/h less, then the time taken would have been one hour more for covering the same distance. How much time (in hours) will he takes to cover a distance of 480 km at his original speed?

(A) 11
(B) 8
(C) 10
(D) 9

Solution: $\begin{aligned} Distance = \frac{S_{1} \times S_{2}}{S_{1} - S_{2}} \times difference of time \\ 240 = \frac{S (S - 8)}{S - S + 8} \times 1 \\ 240 \times 8 = S \times (S - 8) \\ 48 \times 40 = S \times (S - 8) \\ S = 48 km/hr . \\ = \frac{480}{48} = 10 hrs \end{aligned}$

49.

A passenger train 150 m long is travelling with a speed of 36 km/hr. If a man is cycling in the direction of train at 9 km/hr, the time taken by the train to pass the man is :

(A) 10 seconds
(B) 15 seconds
(C) 18 seconds
(D) 20 seconds

Solution: Their relative speed in same direction : = 36 - 9 = 27 km/hr Time taken by train to cross the man = $\frac{150}{27}$ $(Time = \frac{Distance}{Speed})$ $\begin{aligned} Time = \frac{150}{27 \times \frac{5}{18}} \\ [1 km/hr = \frac{5}{18} m/s] \\ Time = \frac{150 \times 18}{27 \times 5} \\ Time = \frac{30 \times 2}{3} \\ ∴ Time = 20 seconds \end{aligned}$

50.

A man goes from Mysore to Bangalore at a uniform speed of 40 km/hr and comes back to Mysore at a uniform speed of 60 km/hr. His average speed for the whole journey is :

(A) 48 km/hr
(B) 50 km/hr
(C) 54 km/hr
(D) 5 km/hr

Solution: $\begin{aligned} Average speed \\ = \frac{2xy}{x + y} \\ = \frac{2 \times 40 \times 60}{40 + 60} \\ ∴ Average speed = 48 km/hr \end{aligned}$

«
1
2
3
4
5
6
7
8
9
10
...
45
46
Next ›
Last »

Indian Polity Mcq IAS GK Question India GK World GK GK questions GK Quiz Biology GK Science GK Physics GK Chemistry GK General Awareness Computer GK Political GK Indian Political GK Economics GK History GK Sports GK Geography GK Teaching Aptitude GK CTET/TET GK B Ed Entrance GK Banking GK SSC GK UPSC GK Indian Army GK Hindi Grammar GK Hindi Grammar MCQ Reasoning questions Bihar GK Rajasthan GK Jharkhand GK MP GK UP GK Chhattisgarh GK Haryana GK HP GK Maharashtra GK Electronics GK Agriculture GK States/Capitals GK Books Name & Author Arthimetic Verbal Reasoning Non Verbal Reasoning English

Practice MCQ Questions and Answer on Speed Time and Distance

General Knowledge