Practice MCQ Questions and Answer on Number Series Completion
151.
Find the missing term: 4, 12, 36, 108, ?
(A) 144
(B) 216
(C) 304
(D) 324
Solution:
The pattern is × 3 So, missing term = 108 × 3 = 324
152.
Find the missing term: 1, 2, 3, 6, 9, 18, ?, 54
(A) 18
(B) 27
(C) 36
(D) 81
Solution:
The pattern is × 2, × 3/2, × 2, × 3/2, × 2,.............So, missing term = 18 × 3/2 = 27
153.
8, 43, 11, 41, __, 39, 17. What number should fill in the blank?
(A) 8
(B) 14
(C) 43
(D) 44
Solution:
This is a simple alternating addition and subtraction series. The first series begins with 8 and adds 3; the second begins with 43 and subtracts 2.
154.
Find the missing term :- 3, 15, ?, 63, 99, 143
(A) 27
(B) 35
(C) 45
(D) 56
Solution:
The terms of the given series are (22 - 1), (42 - 1),................,(82 - 1), (102 - 1), (122 - 1)So, missing term = (62 - 1) = (36 - 1) = 35
155.
Find out the wrong term: 24576, 6144, 1536, 386, 96, 24
(A) 96
(B) 386
(C) 1536
(D) 6144
Solution:
Each term of the series is obtained by dividing the preceding term by 4. So, 1536 is wrong and must be replaced by (1536 ÷ 4) i.e., 384.
156.
9, 11, 33, 13, 15, 33, 17, ... choose which pair of numbers comes next?
(A) 19, 33
(B) 33, 35
(C) 33, 19
(D) 15, 33
Solution:
In this alternating repetition series, a random number, 33, is interpolated every third number into a simple addition series, in which each number increases by 2.
157.
Find the missing term : 3, 5, 9, 17, ?
(A) 33
(B) 42
(C) 26
(D) 65
Solution:
1st term : 3 2nd term : 3 + 2 = 5 3rd term : 5 + 4 = 9 4th term : 9 + 8 = 17 So, 5th term : 17 + 16 = 33
The pattern is × 3, + 4, × 5, + 6, × 7, So, missing term = 1127 + 8 =1135
159.
Find the missing term : 1, 0, 3, 2, 5, 6, ?, 12, 9, 20
(A) 9
(B) 10
(C) 7
(D) 8
Solution:
There are two series in the given question. 1st series: 1, 3, 5, 7, 9 ... ( each next term are generated by adding 2) 2nd series: 0, 2, 6, 12, 20 ... ( each next term are generated by adding 2n [where n=1,2,3,4...])
160.
2, 3, 4, 5, 6, 4, 8, ... choose which pair of numbers comes next?
(A) 9, 10
(B) 4, 8
(C) 10, 4
(D) 9, 4
Solution:
This is an alternating addition series with a random number, 4, interpolated as every third number. In the main series, 1 is added, then 2 is added, then 1, then 2, and so on.