Practice MCQ Questions and Answer on Series Completion
21.
Choose the missing terms out of the given alternatives.
b e d f ? h j ? l
(A) i m
(B) m i
(C) i n
(D) j m
Solution:
The series may be divided into groups as shown: b e d / f ? h / j ? l Clearly in the first group, the second and third letters are respectively three and two steps ahead of the first letter. A similar pattern would follow in the second and third groups.
22.
Choose the correct order of the given alternative : FAK, IEM, LIO, ?
(A) OMQ
(B) OPQ
(C) MNO
(D) NOP
Solution:
F A K +3 +4 +2 I E M +3 +4 +2 L I O +3 +4 +2 O M Q
23.
Choose the missing terms out of the given alternatives : Z, ?, T, N, ?, H, ?, B
(A) W, Q, K, E
(B) W, R, K, E
(C) X, Q, K, E
(D) X, R, K, E
Solution:
Z - 6 T - 6 N - 6 H - 6 BZ -3 W - 3 T - 3 Q- 3 N - 3 K - 3 H - 3 E - 3 B
24.
3, 4, 7, 7, 13, 13, 21, 22, 31, 34, ?
(A) 42
(B) 43
(C) 51
(D) 52
Solution:
The given sequence is a combination of two series : I. 3, 7, 13, 21, 31, ? and II. 4, 7, 13, 22, 34 The pattern in I is + 4, + 6, + 8, + 10,..... The pattern in II is + 3, + 6, + 9, + 12,..... So, missing term = 31 + 12 = 43.
25.
8, 9, 8, 7, 10, 9, 6, 11, 10, ?, 12
(A) 5
(B) 7
(C) 8
(D) 11
Solution:
The given sequence is a combination of three series : I. 1st, 4th, 7th, 10th terms i.e. 8, 7, 6, ? II. 2nd, 5th, 8th, 11th terms i.e. 9, 10, 11, 12 III. 3rd, 6th, 9th terms i.e. 8, 9, 10 The pattern in I is - 1. So, missing term = 6 - 1 = 5.
26.
1, 2, 6, 7, 21, 22, 66, 67, ?
(A) 70
(B) 134
(C) 201
(D) 301
Solution:
The pattern is + 1, x 3, + 1, x 3, + 1, x 3, + 1,..... So, missing term = 67 x 3 = 201.
27.
6, 13,28,59,?
(A) 111
(B) 113
(C) 114
(D) 122
Solution:
1st number : 6 2nd number : 6 X 2 +1 = 13 3rd number : 13 X 2 + 2 = 28 4th number : 28 X 2 + 3 = 59 therefore 5th number : 59 x 2 + 4 = 122
28.
Choose the missing terms out of the given alternatives : DHL, PTX, BFJ ?
(A) CCK
(B) KOS
(C) NRV
(D) RVZ
Solution:
1st letter : D + 12 = P + 12 = B + 12 = N 2nd letter : H + 12 = T + 12 = F + 12 = R 3rd letter : L + 12 = X + 12 = J + 12 = V
29.
3, 7, 15, ?, 63, 127
(A) 30
(B) 31
(C) 47
(D) 52
Solution:
Each number in the series is one more than twice the preceding number. So, missing term = (15 x 2) + 1 = 31.
30.
13, 35, 57, 79, 911, ?
(A) 1110
(B) 1112
(C) 1113
(D) 1315
Solution:
The terms of the given series are numbers formed by joining together consecutive odd numbers in order i.e. 1 and 3, 3 and 5, 5 and 7, 7 and 9, 9 and 11, ..... So, missing term = number formed by joining 11 and 13 = 1113.