The year next to 2003 will have the same calendar as that of the year 2003?
(A) 2024
(B) 2014
(C) 2009
(D) 2020
Solution:
Given year 2003, when divided by 4 leaves a remainder of 3. NOTE: When remainder is 3, 11 is added to the given year to get the result. So, 2003 + 11 = 2014
12.
Which century year is a leap year?
(A) 1900
(B) 1700
(C) 1600
(D) 1100
Solution:
For an century year,it is divided by 400,when leaves a remainder 0 then it is a leap year. So, 1600
13.
How many days will there be from 26th January, 1996 to 15th May, 1996 (both days included)?
(A) 110
(B) 111
(C) 112
(D) 113
Solution:
Number of days from 26-Jan-1996 to 15-May-1996 (both days included) = 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May) = 111
14.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
(A) Sunday
(B) Saturday
(C) Friday
(D) Wednesday
Solution:
On 31st December, 2005 it was Saturday. Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. ∴ On 31st December 2009, it was Thursday. Thus, on 1st Jan, 2010 it is Friday.
15.
If Feb 12th,1986 falls on Wednesday then Jan 1st,1987 falls on which day?
(A) Wednesday
(B) Tuesday
(C) Thursday
(D) Friday
Solution:
First,we count the number of odd days for the left over days in the given period. Here,given period is 12.2.1986 to 1.1.1987 Feb Mar Apr May June July Aug Sept Oct Nov Dec Jan 16 31 30 31 30 31 31 30 31 30 31 1 (left days) 2 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 3 + 1(odd days) = 1 odd day So, given day Wednesday + 1 = Thursday is the required result.
16.
Today is Thursday. What will be the day of the week after 94 days?
(A) Sunday
(B) Monday
(C) Tuesday
(D) Wednesday
Solution:
94 days = (13 × 7) + 3 = 3 odd days. The required day is 3 days beyond Thursday i.e., Sunday
17.
In a year, Holi was enjoyed on 6th March 9 AM and Deepawali (Diwali) was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ?
(A) 2101 hrs
(B) 4125 hrs
(C) 5124 hrs
(D) 6011 hrs
Solution:
From March 6th to November 11th, there are 250 days and Thus 250 x 24 hours So from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.
18.
What day of the week will 22 Apr 2222 be?
(A) Monday
(B) Tuesday
(C) Wednesday
(D) Thursday
Solution:
22 Apr 2222 = (2221 years + period from 1-Jan-2222 to 22-Apr-2222) We know that number of odd days in 400 years = 0 Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400) Number of odd days in the period 2001-2200 = Number of odd days in 200 years = 5 x 2 = 10 = 3 (As we can reduce perfect multiples of 7 from odd days without affecting anything) Number of odd days in the period 2201-2221 = 16 normal years + 5 leap years = 16 x 1 + 5 x 2 = 16 + 10 = 26 = 5 odd days Number of days from 1-Jan-2222 to 22 Apr 2222 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 22(Apr) = 112 112 days = 0 odd day Total number of odd days = (0 + 3 + 5 + 0) = 8 = 1 odd day 1 odd days = Monday Hence 22 Apr 2222 is Monday
19.
January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?
(A) Monday
(B) Tuesday
(C) Wednesday
(D) Sunday
Solution:
The year 2007 is an ordinary year. So, it has 1 odd day. 1st day of the year 2007 was Monday. 1st day of the year 2008 will be 1 day beyond Monday. Hence, it will be Tuesday.
20.
Which year has 366 days?
(A) 1900
(B) 1200
(C) 2500
(D) 1700
Solution:
When a century year leaves a remainder 0, when divided by 400 then it is a leap year (366 days). So, 1200 has 366 days.