The calendar for the year 1988 is same as which upcoming year ?
(A) 2012
(B) 2014
(C) 2016
(D) 2010
Solution:
We already know that the calendar after a leap year repeats again after 28 years. Here 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.
62.
The calendar of year 1939 is same as which year?
(A) 1943
(B) 1964
(C) 1950
(D) 1956
Solution:
Given year 1939, when divided by 4 leaves a remainder of 3. NOTE: When remainder is 3, 11 is added to the given year to get the result. So, 1939 + 11 = 1950
63.
The maximum gap between two successive leap year is?
(A) 4
(B) 8
(C) 2
(D) 1
Solution:
This can be illustrated with an example. Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year). Explanation : The length of the solar year, however, is slightly less than 365$$\frac{1}{4}$$ days-by about 11 minutes. To compensate for this discrepancy, the leap year is omitted three times every four hundred years. In other words, a century year cannot be a leap year unless it is divisible by 400. Thus 1700, 1800, and 1900 were not leap years, but 1600, 2000, and 2400 are leap years.
64.
How many days will there be from 26th January, 1996 to 15th May, 1996 (both days included)?
(A) 110
(B) 111
(C) 112
(D) 113
Solution:
Number of days from 26-Jan-1996 to 15-May-1996 (both days included) = 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May) = 111
65.
Second Saturday and every Sunday is a holiday. How many working days will be there in a month of 30 days beginning on a Saturday?
(A) 21
(B) 22
(C) 23
(D) 24
Solution:
Mentioned month begins on a Saturday and has 30 days Sundays = 2nd, 9th, 16th, 23rd, 30th ⇒ Total Sundays = 5 Every second Saturday is holiday. 1 second Saturday in every month Total days in the month = 30 Total working days = 30 - (5 + 1) = 24
66.
How many leap years do 300 years have?
(A) 75
(B) 74
(C) 72
(D) 73
Solution:
Given year is divided by 4, and the quotient gives the number of leap years. Here, 300 ÷ 4 = 75 But, as 100, 200 and 300 are not leap years ⇒ 75 - 3 = 72 leap years.
67.
On what dates of April, 2001 did Wednesday fall?
(A) 1st, 8th, 15th, 22nd, 29th
(B) 2nd, 9th, 16th, 23rd, 30th
(C) 3rd, 10th, 17th, 24th
(D) 4th, 11th, 18th, 25th
Solution:
We shall find the day on 1st April, 2001. 1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001) Odd days in 1600 years = 0 Odd days in 400 years = 0 Jan. Feb. March April (31 + 28 + 31 + 1) = 91 days ≡ 0 odd days. Total number of odd days = (0 + 0 + 0) = 0 On 1st April, 2001 it was Sunday. In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
68.
What day of the week will 22 Apr 2222 be?
(A) Monday
(B) Tuesday
(C) Wednesday
(D) Thursday
Solution:
22 Apr 2222 = (2221 years + period from 1-Jan-2222 to 22-Apr-2222) We know that number of odd days in 400 years = 0 Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400) Number of odd days in the period 2001-2200 = Number of odd days in 200 years = 5 x 2 = 10 = 3 (As we can reduce perfect multiples of 7 from odd days without affecting anything) Number of odd days in the period 2201-2221 = 16 normal years + 5 leap years = 16 x 1 + 5 x 2 = 16 + 10 = 26 = 5 odd days Number of days from 1-Jan-2222 to 22 Apr 2222 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 22(Apr) = 112 112 days = 0 odd day Total number of odd days = (0 + 3 + 5 + 0) = 8 = 1 odd day 1 odd days = Monday Hence 22 Apr 2222 is Monday
69.
How many times does the 29th day of the month occur in 400 consecutive years?
(A) 4487 times
(B) 4457 times
(C) 4497 times
(D) 4447 times
Solution:
In 400 consecutive years there are 97 leap years. Hence, in 400 consecutive years February has the 29th day 97 times and the remaining eleven months have the 29th day 400 × 11 or 4400 times. Thus the 29th day of the month occurs = 4400 + 97 = 4497 times.
70.
What was the day on 15th august 1947 ?
(A) Friday
(B) Saturday
(C) Sunday
(D) Thursday
Solution:
15th Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947) Odd days in 1600 years = 0 Odd days in 300 years = 1 46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2) = 57 (8 weeks + 1 day) = 1 odd day Jan. Feb. Mar. Apr. May. Jun. Jul. Aug ( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days Hence, as the number of odd days = 5, given day is Friday.