Practice MCQ Questions and Answer on Arithmetic Reasoning

71.

Find the number which when added to itself 13 times, gives 112.

• (A) 7
• (B) 8
• (C) 9
• (D) 11

Show Answer

 Let the number be x. Then, x + 13x = 112 ⇔ 14x = 112 ⇔ x = 8.

72.

A number of friends decided to go on a picnic and planned to spend Rs. 96 on eatables. Four of them, however, did not turn up. As a consequence, the remaining ones had to contribute Rs. 4 each extra. The number of those who attended the picnic was

• (A) 8
• (B) 12
• (C) 16
• (D) 24

Show Answer

73.

At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party ?

• (A) 60
• (B) 65
• (C) 90
• (D) None of these

Show Answer

74.

A bus starts from city X. The number of women in the bus is half of the number of men. In city Y, 10 men leave the bus and five women enter. Now, number of men and women is equal. In the beginning, how many passengers entered the bus ?

• (A) 15
• (B) 30
• (C) 36
• (D) 45

Show Answer

 Originally, let number of women = x. Then, number of men = 2x. So, in city Y, we have : (2x - 10) = (x + 5) or x - 15. Therefore Total number of passengers in the beginning = (x + 2x) = 3x = 45.

75.

A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?

• (A) 12
• (B) 16
• (C) 18
• (D) 24

Show Answer

 Suppose the boy got x sums right and 2x sums wrong. Then, x + 2x = 48 ⇔ 3x = 48 ⇔ x = 16.

76.

A bird shooter was asked how many birds he had in the bag. He replied that there were all sparrows but six, all pigeons but six, and all ducks but six. How many birds he had in the bag in all?

• (A) 9
• (B) 18
• (C) 27
• (D) 36

Show Answer

 There were all sparrows but six' means that six birds were not sparrows but only pigeons and ducks. Similarly, number of sparrows + number of ducks = 6 and number of sparrows + number of pigeons = 6. This is possible when there are 3 sparrows, 3 pigeons and 3 ducks i.e. 9 birds in all.

77.

In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class ?

• (A) 20
• (B) 25
• (C) 30
• (D) Data inadequate

Show Answer

 Let the number of boys and girls participating in sports be 3x and 2x respectively. Then, 3x = 15 or x = 5. So, number of girls participating in sports = 2x = 10. Number of students not participating in sports = 60 - (15 + 10) = 35. Let number of boys not participating in sports be y. Then, number of girls not participating in sports = (35 -y). Therefore (35 - y) = y + 5 ⇔ 2y ⇔ 30 ⇔ y = 15. So, number of girls not participating in sports = (35 - 15) = 20. Hence, total number of girls in the class = (10 + 20) = 30.

78.

A shepherd had 17 sheep. All but nine died. How many was he left with ?

• (A) Nil
• (B) 8
• (C) 9
• (D) 17

Show Answer

 'All but nine died' means 'All except nine died' i.e. 9 sheep remained alive.

79.

A number consists of two digits whose sum is 11. If 27 is added to the number, then the digits change their places. What is the number ?

• (A) 47
• (B) 65
• (C) 83
• (D) 92

Show Answer

 Let the ten's digit be x. Then, unit's digit = (11 - x). So, number = 10x + (11 - x) = 9x + 11. Therefore (9x + 11) + 27 = 10 (11 - x) + x ⇔ 9x + 38 = 110 - 9x ⇔ 18x = 72 ⇔ x = 4. Thus, ten's digit = 4 and unit's digit = 7. Hence, required number = 47.