If 1st October is Sunday, then 1st November will be
(A) Monday
(B) Tuesday
(C) Wednesday
(D) Thursday
Solution:
Given that 1st October is Sunday Number of days in October = 31 31 days = 3 odd days (As we can reduce multiples of 7 from odd days which will not change anything) Hence 1st November = (Sunday + 3 odd days) = Wednesday
2.
How many days are there from 3rd February, 2012 to 18th April 2012 (both inclusive)?
(A) 55 days
(B) 65 days
(C) 76 days
(D) 85 days
Solution:
Here we have to count the number days from 3rd February, 2012 to 18th April 2012 ( both inclusive) The given year is leap year, So February month has 29 days From 3rd to 29th February = 27 days In March = 31 days From 1st to 18th April = 18 days Total number of days = 27 + 31 + 18 = 76 days
3.
What was the day on 2nd Jan 1901 ?
(A) Tuesday
(B) Wednesday
(C) Monday
(D) Thursday
Solution:
2nd Jan 1901 means (1900 years and 2 day) Now, 1600 years have 0 odd day 300 years have 1 odd day 2 days has 2 odd day Total no. of odd days = 0 + 1 + 2 = 3 days Hence, the day on 2nd Jan 1901 was Wednesday.
4.
What day of the week was 20th June 1837?
(A) Monday
(B) Tuesday
(C) Wednesday
(D) Thursday
Solution:
20th June, 1837 means 1836 complete years + first 5 months of the year 1837 + 20 days of June 1600 years give no odd days 200 years give 3 odd days 36 years give (36 + 9 ) or 3 odd days Thus 1836 years give 6 odd days From 1st January to 20th June there are 3 odd days Odd days: January 3, February 0, March 3, April 2, May 3, June 6 = 17 Thus the total number of odd days = 6 + 3 or 2 odd days This means that the 20th of June fell on 2nd day commencing from Monday. The required day was Tuesday.
5.
Which year has 366 days?
(A) 1900
(B) 1200
(C) 2500
(D) 1700
Solution:
When a century year leaves a remainder 0, when divided by 400 then it is a leap year (366 days). So, 1200 has 366 days.
6.
The calendar for the year 1988 is same as which upcoming year ?
(A) 2012
(B) 2014
(C) 2016
(D) 2010
Solution:
We already know that the calendar after a leap year repeats again after 28 years. Here 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.
7.
Today is 3rd November. The day of the week is Monday. This is a leap year. What will be the day of the week on this date after 3 years?
(A) Monday
(B) Tuesday
(C) Wednesday
(D) Thursday
Solution:
This is a leap year. So, none of the next 3 years will be leap years. Each year will give one odd day so the day of the week will be 3 odd days beyond Monday i.e. it will be Thursday.
8.
On 19th June, 1984 Monday falls. What day of the week was it on 19th June, 1985?
(A) Sunday
(B) Monday
(C) Tuesday
(D) Wednesday
Solution:
The year 1985 is an ordinary year. So, it has 1 odd day. So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984. But, 19th June,1984 is Monday So, 19th June, 1985 is Tuesday.
9.
How many times does the 29th day of the month occur in 400 consecutive years?
(A) 4487 times
(B) 4457 times
(C) 4497 times
(D) 4447 times
Solution:
In 400 consecutive years there are 97 leap years. Hence, in 400 consecutive years February has the 29th day 97 times and the remaining eleven months have the 29th day 400 × 11 or 4400 times. Thus the 29th day of the month occurs = 4400 + 97 = 4497 times.
10.
In a year, Holi was enjoyed on 6th March 9 AM and Deepawali (Diwali) was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ?
(A) 2101 hrs
(B) 4125 hrs
(C) 5124 hrs
(D) 6011 hrs
Solution:
From March 6th to November 11th, there are 250 days and Thus 250 x 24 hours So from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.