Practice MCQ Questions and Answer on Percentage

121.

A shopkeeper bought 20 kg of rice at Rs. 55 per kg, 25 kg of rice at Rs. 50 per kg, and 35 kg of rice at Rs. 60 per kg. He spent a sum of Rs. 150 on transportation. He mixed all the three types of rice and sold all the stock at Rs. 62.56 per kg. His profit percent in the entire transaction is:

(A) 8.8
(B) 12.5
(C) 10.5
(D) 9.2

Solution: Rs. 55 per kg → 20 kg Rice Rs. 50 per kg → 25 kg Rice Rs. 60 per kg → 35 kg Rice 55 × 20 = Rs. 1100 50 × 25 = Rs. 1250 60 × 35 = $\underset{―}{Rs . 2100}$ = Rs. 4450 + Rs. 150 Total Rice 80 kg → Rs. 4600 1 kg → Rs. 57.50 62.56 57.50 $\overset{―}{5.06}$ $\frac{5.06}{57.5}$ × 100 = 8.8%

122.

A customer asks for the production of x number of goods. The company produces y number of goods daily. Out of which z% are units for sale. The order will be completed in :

(A) $\frac{x}{100 y \times (1 - z)} days$
(B) $\frac{100 y z}{x} days$
(C) $\frac{100 x}{(100 - z) y} days$
(D) $\frac{100}{y \times (z - 1)} days$

Solution: $\begin{aligned} Daily supply, \\ = (100 - z) % of y \\ = \frac{(100 - z) y}{100} \\ Thus, required number of days \\ = \frac{100 x}{(100 - z) y} \end{aligned}$

123.

What is 20% of 25% of 300 ?

(A) 150
(B) 60
(C) 45
(D) 15

Solution: Required answer = 300 × $\frac{1}{4}$ × $\frac{1}{5}$ = 15

124.

125% of 860 + 75% of 480 = ?

(A) 1415
(B) 1385
(C) 1435
(D) None of these

Solution: $\begin{aligned} \frac{125 \times 860}{100} + \frac{75 \times 480}{100} \\ = 1075 + 360 \\ = 1435 \end{aligned}$

125.

An empty fuel tank of a car was filled with A type petrol. When the tank was half-empty, it was filled with B type petrol. Again when the tank was half-empty, it was filled with A type petrol. When the tank was half-empty again, it was filled with B type petrol. What is the percentage of A type petrol at present in the tank?

(A) 33.5%
(B) 37.5%
(C) 40%
(D) 50%

Solution: Let the capacity of the tank be 100 litres Initially: A type petrol = 100 litres After first operation: A type petrol = $\frac{100}{2}$ = 50 litres B type petrol = 50 litres After second operation: A type petrol = $\frac{50}{2}$ + 50 = 75 litres B type petrol = $\frac{50}{2}$ = 25 litres After third operation: A type petrol = $\frac{75}{2}$ = 37.5 litres B type petrol = $\frac{25}{2}$ + 50 = 62.5 litres Required percentage = 37.5%

126.

If 80% of A = 50% of B and B = x% of A, then the value of x is :

(A) 400
(B) 300
(C) 160
(D) 150

Solution: 80% of A = 50% of B ⇒ $\frac{80}{100}$ A = $\frac{50}{100}$ B ⇒ 8A = 5B ⇒ A = $\frac{5}{8}$ B Put value of A in given equation, B = x% of A ⇒ B = $\frac{x}{100}$ × $\frac{5}{8}$ B ⇒ x = $\frac{100 \times 8}{5}$ ⇒ x = 160

127.

If the numerator of a fraction is increased by 60% and the denominator is increased by 40%, then resultant fraction is $\frac{16}{63} .$ ÃÂÃÂ The original fraction is:

(A) $\frac{2}{9}$
(B) $\frac{5}{9}$
(C) $\frac{2}{11}$
(D) $\frac{4}{9}$

Solution: $\begin{aligned} Let numerator = 5 x \\ denominator = 5 y \\ So as per question \\ \frac{5 x + 3 x}{5 y + 2 y} = \frac{16}{23} \to \frac{x}{y} = \frac{2}{9} \\ So the original fraction \frac{5 x}{5 y} = \frac{2}{9} \end{aligned}$

128.

In an examination 36% are pass marks. If an examine gets 17 marks and fails by 10 marks, what are the maximum marks?

(A) 90
(B) 75
(C) 60
(D) 55

Solution: Pass mark = (17 + 10) = 27 Let maximum marks be x Then 36% of x = 27 Or, $\frac{36 x}{100}$ = 27 Or, 36x = 2700 Hence, x = 75

129.

The schedule working hour of a labour in a week if 48 hours and he gets Rs. 480 for that. Over time rate is 25% more than the the basic salary rate. In a week a labour gets Rs. 605, how many hours altogether he works in that week.

(A) 49 hours
(B) 52 hours
(C) 55 hours
(D) 58 hours

Solution: Schedule working hours in week = 48 Total pay in a week for schedule working hours = Rs. 480 Pay per hour for schedule working hours = $\frac{480}{48}$ = Rs. 10 Pay per hour for over time = 10 + 25% of 10 = Rs. 12.5 Total pay in that particular week = Rs. 605 Extra pay = 605 - 480 = 125 So, total over time = $\frac{125}{12.5}$ = 10 hours Thus, total work hour altogether in that week = 48 + 10 = 58 hours

130.

If 120 is 20% of a number, then 120% of that number will be :

(A) 20
(B) 120
(C) 480
(D) 720

Solution: Let the number = x According to the question, x × $\frac{20}{100}$ = 120 x = 600 Required answer = 600 × $\frac{120}{100}$ = 720 Alternate 20% represents → 120 1% → $\frac{120}{20}$ So, 120% = $\frac{120}{20}$ × 120 = 720

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Practice MCQ Questions and Answer on Percentage

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