Practice MCQ Questions and Answer on Percentage

141.

If x% of a is the same as y% of b, then z% of b is :

(A) $\frac{x y}{z} % of a$
(B) $\frac{y z}{x} % of a$
(C) $\frac{x z}{y} % of a$
(D) None of these

Solution: $\begin{aligned} x % of a = y % of a \\ \Rightarrow \frac{x}{100} a = \frac{y}{100} b \\ \Rightarrow b = (\frac{x}{y}) a \\ ∴ z % of b : \\ = (z % of \frac{x}{y}) a \\ = (\frac{x z}{y \times 100}) a \\ = (\frac{x z}{y}) % of a \end{aligned}$

142.

The population of a town is 8500. It increases by 20% in the first year and by another 25% in the second year. What would be the population of the town after 2 years ?

(A) 10950
(B) 11950
(C) 12550
(D) 12750

Solution: Population after 2 years : $\begin{aligned} = 8500 \times (1 + \frac{20}{100}) (1 + \frac{25}{100}) \\ = (850 \times \frac{6}{5} \times \frac{5}{4}) \\ = 12750 \end{aligned}$

143.

If a% of x is equal to b% of y, then of c% of y is what % of x ?

(A) c %
(B) $\frac{ac}{b}$ %
(C) $\frac{bc}{a}$ %
(D) abc %

Solution: $\begin{aligned} \frac{a x}{100} = \frac{b y}{100} \\ o r, a x = b y \\ \Rightarrow y = \frac{a x}{b} \\ c % of y = \frac{c y}{100} \\ o r, \frac{c y}{100} = \frac{c a x}{100 b} \\ Thus, \\ c % of y = \frac{c a}{b} % of x \end{aligned}$

144.

Ms. Pooja invests 13% of her monthly salary, i.e., Rs. 8554 in Mediclaim Policies. Later she invests 23% of her monthly salary on Child Education Policies; also she invests another 8% of her monthly salary on Mutual Funds. What is the total annual amount invested by Ms. Pooja ?

(A) Rs. 28952
(B) Rs. 43428
(C) Rs. 173712
(D) Rs. 347424

Solution: Let Pooja's monthly salary be = Rs. x Then, 13% of x = 8554 ⇒ $\frac{13 x}{100}$ = 8554 ⇒ x = $\frac{8554 \times 100}{13}$ ⇒ x = 65800 Total percentage of salary invested = (13 + 23 + 8)%= 44% ∴ Total amount invested monthly = 44% of Rs. 65800 = Rs. $\frac{44}{100}$ × 65800 = Rs. 28952

145.

Distance between A and B is 72 km. Two men started walking from A and B at the same time towards each other. The person who started from A traveled uniformly with average speed of 4 km/hr. The other man traveled with varying speed as follows: In the first hour his speed 2 km/hr, in the second hour it was 2.5 km/hr, in the third hour it was 3 km/hr, and so on. When / where will they meet each other?

(A) 7 hours after starting
(B) 10 hours after starting
(C) 35 km from A
(D) Mid-way between A and B

146.

A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:

(A) 588 apples
(B) 600 apples
(C) 672 apples
(D) 700 apples

Solution: Suppose originally he had x apples Then, $\begin{aligned} (100 - 40) % of x = 420 \\ \Rightarrow \frac{60}{100} \times x = 420 \\ \Rightarrow x = \frac{420 \times 100}{60} = 700 \end{aligned}$

147.

If 49% of X = Y, then Y% of 50 is:

(A) 40% of Y
(B) 24.5% of Y
(C) 50% of X
(D) 24.5% of X

Solution: $\begin{aligned} \frac{X \times 49}{100} = Y \\ \frac{X}{Y} = \frac{100}{49} \\ 50 \times Y % \\ = \frac{2 \times 50 \times 49 %}{2} \\ = \frac{100 \times 49 %}{2} \\ = X \times 24.5 % \end{aligned}$

148.

Mr. X salary increased by 20%. On the increase, the tax rate is 10% higher. The percentage increase in tax liability is:

(A) 20%
(B) 22%
(C) 23%
(D) 24%

Solution: Let his original salary be Rs. 100 Salary after increment = Rs. 120 Let the tax on original salary be 20% and now tax on increased salary (Rs. 20) will be 22% i.e. Rs. 4.40 Thus, increase in tax liability $= \frac{4.40}{20} \times 100 = 22 %$

149.

What percentage of 3.6 kg is 72 gms. ?

(A) 32%
(B) 22%
(C) 12%
(D) 2%

Solution: Required percentage : = $\frac{72}{3.6 \times 1000}$ × 100 = 2%

150.

The population of village is 1,00,000. The rate of increase is 10% per annum. Find the population at the start of the third year?

(A) 1,33,100
(B) 1,21,000
(C) 1,18,800
(D) 1,20,000

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Practice MCQ Questions and Answer on Percentage

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