Practice MCQ Questions and Answer on Percentage

131.

50 minutes is what percentage of a day (approx.)-

(A) 3.5%
(B) 4%
(C) 5%
(D) 6%

132.

45% of 300 + $\sqrt{?}$ = 56% of 750 - 10% of 250

(A) 60
(B) 130
(C) 260
(D) 67600

Solution: Let 45% of 300 + $\sqrt{x}$ = 56% of 750 - 10% of 250 Then, $(\frac{45}{100} \times 300) + \sqrt{x} = (\frac{56}{100} \times 750)$ $- (\frac{10}{100} \times 250)$ $\begin{aligned} \Rightarrow 135 + \sqrt{x} = 420 - 25 \\ \Rightarrow \sqrt{x} = 260 \\ \Rightarrow x = {(260)}^{2} \\ \Rightarrow x = 67600 \end{aligned}$

133.

A man spends a part of his monthly income and saves the rest. The ratio of his expenditure to the saving is 61 : 6. If his monthly income is Rs. 8710, the amount of his monthly savings is :

(A) Rs. 870
(B) Rs. 690
(C) Rs. 980
(D) Rs. 780

Solution: Expense + Saving = Income 61 + 6 = 67 67 units = Rs. 8710 1 unit = $\frac{8710}{67}$ = 130 6 unit = Rs. 780

134.

When the price of an article was reduce by 20%, its sale increased by 80%. What was the net effect on the sale ?

(A) 44% increase
(B) 44% decrease
(C) 66% increase
(D) 75% increase

Solution: Let conside 100 item sold on Rs.100 ∴ Total Amount = 100 × 100 = Rs. 10000 Now After 20% discount price become Rs.80 Total Number of Sale increased after discount is 80%. i.e. 100 + 80% of 100 = 180(Item sold) ∴ Total Amount = 180 × 80 = Rs. 14400 Increased in amount = 14400 - 10000 = 4400 % Increase in amount = $\frac{4400 \times 100}{10000}$ = 44% (increase)

135.

If three-fifth of sixty percent of a number is 36, the number is :

(A) 100
(B) 80
(C) 75
(D) 90

Solution: Let the number be x According to the question, x × $\frac{60}{100}$ × $\frac{3}{5}$ = 36 ⇒ x = $\frac{36 \times 25}{9}$ ⇒ x = 100

136.

If decreasing 110 by x% gives the same result as increasing 50 by x%, then x% of 650 is what percentage (correct to the nearest integer) more than (x - 10)% of 780?

(A) 17%
(B) 12%
(C) 18%
(D) 14%

Solution: $\begin{aligned} 110 \times \frac{(100 - x)}{100} = 50 \times \frac{(100 + x)}{100} \\ 11 (100 - x) = 5 (100 + x) \\ 1100 - 11 x = 500 + 5 x \\ 16 x = 600 \\ x = \frac{800}{16} = \frac{75}{2} = 37 \frac{1}{2} % \\ Now, \\ 650 \times \frac{75}{200} \to 780 \times \frac{55}{200} \\ \frac{25}{2} \to 11 \\ 25 \to 22 \\ = \frac{3}{22} \times 100 = 14 % \end{aligned}$

137.

One bacterium splits into eight bacteria of the next generation. But due to environment, only 50% of one generation can produced the next generation. If the seventh generation number is 4096 million, what is the number in first generation?

(A) 1 million
(B) 2 million
(C) 4 million
(D) 8 million

Solution: Let the number of bacteria in the 1st generation be x, then number of bacteria in 2nd, 3rd, 4th . . . . . Generation would be $8 (\frac{x}{2}), 8 (\frac{4 x}{2}), 8 (\frac{16 x}{2})$ . . . . And so on. As x, 4x, 16x, 64x . . . . . it is in GP with common ratio 4 Hence, 7th term of GP, x(4)6 = 4096 or, x = 1 or 1 million.

138.

The ratio of the number of boys and girls in school at 8 : 12. If 50% of boys and 25% of girls are getting scholarship for their studies, what is the percentage of school students who are not getting any scholarships ?

(A) 65%
(B) 66%
(C) 67%
(D) 68%

Solution: Let the number of boys is = 8x Number of girls = 12x Boys are not getting scholarship = 8x × $\frac{1}{2}$ = 4x Girls are not getting scholarship = 12x × $\frac{3}{4}$ = 9x % of students not getting scholarship = $\frac{(4 x + 9 x)}{20 x}$ × 100 = 65%

139.

Every month a man consumes 25 kg rice and 9 kg wheat. The price of rice is 20% of the price of wheat and thus he spends total Rs. 350 on the rice and wheat per month. If the price of wheat is increased by 20% then what is the percentage reduction of rice consumption for the same expenditure of Rs. 350? Given that the price of rice and consumption of wheat is constant :

(A) 40%
(B) 25%
(C) 36%
(D) 24%

Solution: Let the price of wheat is x per kg. Then price of wheat will be 5x per kg. Expenditure on rice = 25 × x = 25x Expenditure of wheat = 9 × 5x = 45x Total cost, 25x + 45x = 350 70x = 350 x = 5 Hence, price of Rice = Rs. 5 per kg. Price of wheat = 25 per kg. Now, price of wheat = 25 ---- 20% ↑----> Rs. 30 per kg. Let the new amount of rice is N kg, then N*5 + 9*30 = 350 N = 16 kg. % decrease in the amount of rice $\begin{aligned} = \frac{(25 - 16) \times 100}{25} \\ = 36 % \end{aligned}$

140.

The population of a town increases every year by 4%. If its present population is 50,000, then after 2 years it will be

(A) 53,900
(B) 54,000
(C) 54,080
(D) 54,900

Solution: Here we can use the compound interest based formula, $\begin{aligned} Population after n years \\ = P \times {[1 + \frac{r}{100}]}^{n} \\ Population after 2 years \\ = 50000 \times {[1 + \frac{4}{100}]}^{2} \end{aligned}$ Population after 2 years = 54080 Alternatively, we can use, net percentage change graphic as well, 50,000------4%↑---→ 52,000---- 4%↑---→ 54,080. Then, population after 2 years= 54,080. In this calculation, we need to find 1% of 50,000 first, which is easily calculated by dividing 50,000 by 100.

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Practice MCQ Questions and Answer on Percentage

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