Practice MCQ Questions and Answer on Percentage

481.

In an examination, questions were asked in five sections. Out of the total students, 5% candidates cleared the cut-off in all the sections and 5% cleared none. Of the rest, 25% cleared only one section and 20% cleared four sections. If 24.5% of the entire candidates cleared two sections and 300 candidates cleared three sections. Find out how many candidates appeared at the examination?

(A) 1000
(B) 1200
(C) 1500
(D) 2000

482.

A sample of 50 litres of glycerine is found to be adulterated to the extent of 20%. How much pure glycerine should be added to it so as to bring down the percentage of impurity to 5% ?

(A) 155 litres
(B) 150 litres
(C) 150.4 litres
(D) 140 litres

483.

If 30% of A is added to 40% of B, the answer is 80% of B. What percentage of A is B ?

(A) 30%
(B) 40%
(C) 70%
(D) 75%

Solution: According to the question, $\frac{30 A}{100}$ + $\frac{40 B}{100}$ = $\frac{80 B}{100}$ 30A = 40B ⇒ 3A = 4B ⇒ A = $\frac{4 B}{3}$ Required % = $\frac{B}{A}$ × 100 = $\frac{B \times 3}{4 B}$ × 100 = 75%

484.

In an institute, 60% of the students are boys and the rest are girls. Further 15% of the boys and 7.5% of the girls are getting a fee waiver. If the number of those getting a fee waiver is 90, find the total number of students getting 50% concessions if it is given that 50% of those not getting a fee waiver are eligible to get half fee concession?

(A) 360
(B) 280
(C) 320
(D) 330

Solution: Let us assume there are 100 students in the institute. Then, number of boys = 60 And, number of girls = 40 Further, 15% of boys get fee waiver = 9 boys 7.5% of girls get fee waiver = 3 girls Total = 12 students who gets fee waiver But, here given 90 students are getting fee waiver. So we compare 12 = 90 So, 1 = $\frac{90}{12}$ = 7.5 Now number of students who are not getting fee waiver = 51 boys and 37 girls 50% concession = 25.5 boys and 18.5 girls (i.e. total 44) Hence, required students = 44 × 7.5 = 330

485.

Find the : 38% of 341 = ?

(A) 120.68
(B) 129.58
(C) 135.78
(D) 136.28

Solution: = 38% of 341 = $\frac{38}{100}$ × 341 = $\frac{12958}{100}$ = 129.58

486.

Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.

(A) 2 : 3
(B) 1 : 1
(C) 3 : 4
(D) 4 : 3

Solution: $\begin{aligned} 5 % of A + 4 % of B = \frac{2}{3} (6 % of A + 8 of B) \\ \Rightarrow \frac{5}{100} A + \frac{4}{100} B = \frac{2}{3} (\frac{6}{100} A + \frac{8}{100} B) \\ \Rightarrow \frac{1}{20} A + \frac{1}{25} B = \frac{1}{25} A + \frac{4}{75} B \\ \Rightarrow (\frac{1}{20} - \frac{1}{25}) A = (\frac{4}{75} - \frac{1}{25}) B \\ \Rightarrow \frac{1}{100} A = \frac{1}{75} B \\ \frac{A}{B} = \frac{100}{75} = \frac{4}{3} \\ ∴ Required ratio = 4 : 3 \end{aligned}$

487.

In a certain organisation, 40% employees are matriculates, 50% of the remaining are graduates and the remaining 180 are post-graduates. What is the number of graduate employees ?

(A) 180
(B) 240
(C) 300
(D) 360

Solution: Let the total number of employees be x Then, (100 - 50)% of (100 - 40)% of x = 180 50% of 60% of x = 180 $\begin{aligned} \Rightarrow (\frac{50}{100} \times \frac{60}{100} \times x) = 180 \\ \Rightarrow x = (\frac{180 \times 10}{3}) \\ \Rightarrow x = 600 \end{aligned}$ ∴ Number of graduate employees : $=$ 50% of 60% of x $\begin{aligned} = (\frac{50}{100} \times \frac{60}{100} \times 600) \\ = 180 \end{aligned}$

488.

If the price of erasers goes down by 25%, a man can buy 2 more erasers for a rupee. How many erasers are available for a rupee ?

(A) 2
(B) 4
(C) 6
(D) 8

Solution: Let the original price of an eraser be Rs. x Reduced price = 75% of Rs. x = Rs. $\frac{3 x}{4}$ $\begin{aligned} ∴ \frac{1}{(\frac{3 x}{4})} - x = 2 \\ \Rightarrow \frac{4}{3 x} - \frac{1}{x} = 2 \\ \Rightarrow \frac{1}{3 x} = 2 \\ \Rightarrow 6 x = 1 \\ \Rightarrow x = \frac{1}{6} \end{aligned}$ Hence, number of erasers available for a rupee = 6

489.

Population of a district is 2,96,000 out of which 1,66,000 are male. 50% of the population is literate. If 70% males are literate, then the number of woman who are literate, is

(A) 32,200
(B) 31,800
(C) 66,400
(D) 48,000

490.

The population of a town increases every year by 4%. If population was 50000 in starting, then after two years will be :

(A) 53900
(B) 54000
(C) 54080
(D) 54900

Solution: 4% = $\frac{1}{25}$ $\begin{matrix} Initial Final \\ 25 26 \\ 25 26 \\ \overset{―}{625 676} \end{matrix}$ According to the question, 625 units = 50000 1 unit = $\frac{50000}{625}$ = 80 676 units = 80 × 676 = 54080 Hence, population after two years = 54080

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Practice MCQ Questions and Answer on Percentage

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