Practice MCQ Questions and Answer on Percentage

501.

In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is $\frac{2}{3}$ of the number of students of 8 years of age which is 48. What is the total number of students in the school?

(A) 72
(B) 80
(C) 120
(D) 150

Solution: Answer & Solution Answer: Option E Solution: Let the number of students be x. Then, Number of students above 8 years of age $\begin{aligned} = (100 - 20) % of x = 80 % of x \\ ∴ 80 % of x = 48 + \frac{2}{3} of 48 \\ \Rightarrow \frac{80}{100} x = 80 \\ \Rightarrow x = 100 \end{aligned}$

502.

In a college, 40% of the students were allotted group A, 75% of the remaining were given group B and the remaining 12 students were given group C. Then the number of students who applied for the group is :

(A) 100
(B) 60
(C) 80
(D) 92

Solution: Let total number of student apply in college 100x 40% student alloted in group A , i.e. 40x Remaining Student 100x - 40x = 60x Now 75% of remaining student got alloted in Group B i.e. 75% of 60x = 45x Remain student is 60x - 45x = 15x (which alloted in Group C) According to question 15x = 12 x = $\frac{12}{15}$ Total Number of Student applied in college = 100x = 100 x $\frac{12}{15}$ = 80

503.

In the recent, climate conference in New York, out of 700 men, 500 women, 800 children present inside the building premises, 20% of the men, 40% of the women and 10% of the children were Indians. Find the percentage of people who were not Indian?

(A) 77%
(B) 73%
(C) 79%
(D) 83%

Solution: Number of Indians men present there = $\frac{700 \times 20}{100} = 140$ Indian women = $\frac{500 \times 40}{100} = 200$ Indian children = $\frac{800 \times 10}{100} = 80$ Total member present in climate conference = 700 + 500 + 800 = 2000 Total Indian = 200 + 140 + 80 = 420 Hence, % of Indian present there = $\frac{420 \times 100}{2000} = 21 %$ % of people who were not Indian = 100 - 21 = 79%

504.

The monthly salaries of A and B are the same. A, B and C donate 10%, 8% and 9% respectively, of their monthly salaries to a charitable trust. The difference between the donations of A and B is Rs. 400. The total donation by A and B is Rs. 900 more than that of C. What is the monthly salary of C?

(A) Rs. 25,000
(B) Rs. 30,000
(C) Rs. 27,000
(D) Rs. 36,000

Solution: Let the salary of A and B be 100x each and C be 100y Money donate by A = 100x × $\frac{10}{100}$ = 10x Money donate by B = 100x × $\frac{8}{100}$ = 8x Money donate by C = 100y × $\frac{9}{100}$ = 9y According to the question ⇒ 10x - 8x = 400 ⇒ 2x = 400 ⇒ x = 200 Total donation of A and B = 10x + 8x = 18x ⇒ 18 × 200 = 3600 The total donation by A and B is Rs. 900 more than that of C ⇒ 3600 - 9y = 900 ⇒ 9y = 2700 ⇒ y = 300 Monthly salary of C = 100y = 100 × 300 = 30000 ∴ Monthly salary of C is Rs. 30000

505.

How much $66 \frac{2}{3}$ % of Rs. 312 exceeds Rs. 200 ?

(A) Rs. 96
(B) Rs. 4
(C) Rs. 8
(D) Rs. 104

Solution: $66 \frac{2}{3}$ % of Rs. 312/- exceeds Rs. 200 by Rs. $x$ According to the question, required difference $\begin{aligned} x = Rs . (312 \times \frac{200}{3} % - 200) \\ x = Rs . (312 \times \frac{200}{3 \times 100} - 200) \\ x = Rs . (312 \times \frac{200}{300} - 200) \\ x = Rs . (208 - 200) \\ x = Rs . 8 \end{aligned}$

506.

When the price of an item was reduced by 20%, its sale increased by x%. If there is an increase of 25% in receipt of the revenue, then the value of x is:

(A) 54.35
(B) 57.75
(C) 56.25
(D) 55.35

Solution: $20 % = \frac{1}{5}$ $\begin{matrix} Price & Total & Sales \\ Old \to & 5 & 100 & \frac{100}{5} & = 20 \\ New \to & 4 & 125 & \frac{125}{4} & = 31.25 \end{matrix}$ $\begin{aligned} Increase in sale = 31.25 - 20 = 11.25 \\ Increase % = \frac{11.25}{20} \times 100 = 56.25 % \end{aligned}$

507.

Solve : 105.27% of 1200.11 + 11.80% of 2360.85 = 21.99% of (?) + 1420.99

(A) 500
(B) 240
(C) 310
(D) 550

Solution: 105.27% of 1200.11 + 11.80% of 2360.85 = 21.99% of (?) + 1420.99 ⇒ 105% of 1200 + 12% of 2360 = 22% of (?) + 1421 ⇒ $\frac{105 \times 1200}{100} + \frac{12 \times 2360}{100} =$ $\frac{22 \times (?)}{100}$ $+ 1421$ $\Rightarrow \frac{22 \times (?)}{100} = 1260 + 283.30$ $- 1421$ $\begin{aligned} \Rightarrow \frac{22 \times (?)}{100} = 1543 - 1421 \\ \Rightarrow \frac{22 \times (?)}{100} = 122 \\ ∴ (?) = \frac{122 \times 100}{22} \\ \Rightarrow (?) = \frac{122 \times 50}{11} \\ \Rightarrow (?) = 554.5 (a p p r o x i m a t e 550) \end{aligned}$

508.

In an examination, 5% of the applicants were found ineligible and 85% of the eligible candidates belonged to the general category. If 4275 eligible candidates belonged to other categories, then how many candidates applied for the examinations ?

(A) 30000
(B) 35000
(C) 37000
(D) None of these

Solution: Let the total number of applicants be $x$ Number of eligible candidates = 95 % of $x$ Eligible candidates of other categories = 15% of (95 of $x$ ) = $(\frac{15}{100} \times \frac{95}{100} \times x)$ = $\frac{57 x}{400}$ ∴ $\frac{57 x}{400}$ = 4275 ⇒ $x$ = $(\frac{4275 \times 400}{57})$ ⇒ $x$ = 30000

509.

If x% of 500 = y% of 300 and x% of y% of 200 = 60, then x = ?

(A) $10 \sqrt{2}$
(B) $20 \sqrt{2}$
(C) $15 \sqrt{2}$
(D) $30 \sqrt{2}$

Solution: $\begin{aligned} x % of 500 = y % of 300 \\ \Rightarrow \frac{x}{100} \times 500 = \frac{y}{100} \times 300 \\ \Rightarrow 5 x = 3 y \\ \Rightarrow y = \frac{5}{3} x \\ x % of y % of 200 = 60 \\ \Rightarrow \frac{x}{100} \times \frac{y}{100} \times 200 = 60 \\ \Rightarrow x y = 3000 \\ \Rightarrow x \times \frac{5}{3} x = 3000 \\ \Rightarrow x^{2} = 3000 \times \frac{3}{5} \\ \Rightarrow x^{2} = 1800 \\ \Rightarrow x = 30 \sqrt{2} \end{aligned}$

510.

In an examination, 30% and 35% students respectively failed in History and Geography while 27% students failed in both subjects. If the number of students passing the examination is 248, find the total number of students who appeared in the examination.

(A) 380
(B) 400
(C) 425
(D) 725

Solution: Percentage of failed candidates = (30 + 35 - 27)% = 38% Percentage of passed candidates = (100 - 38)% = 62% Let the total number of students appeared be x Then, 62% of x = 248 ⇒ x = $\frac{248 \times 100}{62}$ ⇒ x = 400

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Practice MCQ Questions and Answer on Percentage

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