Practice MCQ Questions and Answer on Percentage

531.

Two persons contested an election of Parliament. The winning candidate secured 57% of the total votes polled and won by a majority of 42000 votes. The number of total votes polled is :

(A) 500000
(B) 600000
(C) 300000
(D) 400000

532.

Subtracting 6% of x from x is equivalent to multiplying x by how much ?

(A) 0.094
(B) 0.94
(C) 9.4
(D) 94

Solution: Let x - 6% of x = xz Then, ⇔ 94% of x = xz ⇔ $\frac{94 x}{100}$ × $\frac{1}{x}$ = z ⇔ z = 0.94

533.

If (x + 20)% of 250 is 25% more than x% of 220, then 10% of (x + 50) is what percent less than 15% of x?

(A) $16 \frac{2}{3}$
(B) $8 \frac{1}{3}$
(C) $13 \frac{1}{3}$
(D) $33 \frac{1}{3}$

Solution: $\begin{aligned} \frac{250 \times (x + 20)}{100} = \frac{220 \times x}{100} \times \frac{125}{100} \\ 25 x + 500 = 22 \times x \times \frac{5}{4} \\ 100 x + 2000 = 110 x \\ 10 x = 2000 \\ x = 200 \\ \frac{(x + 50) \times 10}{100} = \frac{250 \times 10}{100} = 25 \\ \frac{x \times 15}{100} = \frac{200 \times 15}{100} = 30 \\ Less % = \frac{5}{30} \times 100 = 16 \frac{2}{3} % \end{aligned}$

534.

In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State ?

(A) 7600
(B) 8000
(C) 8400
(D) 8800

535.

In a year, a man manages to sell only 65% of the chicken he owns. How many chicken should the man own to sell 47775 chicken in a years ?

(A) 55000
(B) 68500
(C) 73000
(D) 82500

Solution: Answer & Solution Answer: Option E Solution: Let the required number of chicken be x Then, 65% of x = 47775 $\begin{aligned} \Rightarrow \frac{65}{100} x = 47775 \\ \Rightarrow x = \frac{47775 \times 100}{65} \\ \Rightarrow x = 73500 \end{aligned}$

536.

Nagaraj could save 10% of his income. But 2 years later, when his income increased by 20%, he could save the same amount only as before. By how much percentage has his expenditure increased ?

(A) $22 \frac{2}{9} %$
(B) $23 \frac{1}{3} %$
(C) $24 \frac{2}{9} %$
(D) $25 \frac{2}{9} %$

Solution: Let, his income be = Rs. 100 Saving = Rs. 10 Expenditure = Rs. 90 Increased income = Rs. 120 Increased expenditure = Rs. 110 Increased in expenditure : $\begin{aligned} = \frac{110 - 90}{90} \times 100 \\ = \frac{200}{9} \\ = 22 \frac{2}{9} % \end{aligned}$

537.

Solve this :
(23.6% of 1254) - (16.6% of 834) = ?

(A) 153.5
(B) 155.5
(C) 157.5
(D) 159.5

Solution: $(23.6 % of 1254) - (16.6 % of 834)$ $= (\frac{236}{10} \times \frac{1}{100} \times 1254) -$ $(\frac{166}{10} \times \frac{1}{100} \times 834)$ $\begin{aligned} = \frac{1}{1000} (236 \times 1254 - 166 \times 834) \\ = \frac{12}{1000} (24662 - 11537) \\ = (\frac{12 \times 13125}{1000}) \\ = 157.5 \end{aligned}$

538.

Due to fall of 10% in the rate of sugar, 500 gm more sugar can be purchased for Rs. 140. Find the original rate?

(A) Rs. 31.11
(B) Rs. 29.22
(C) Rs. 33.11
(D) Rs. 32.22

Solution: Money spent originally = Rs. 140 Less Money to be spent now = 10% of 140 = Rs. 14 Rs. 14 now yield 500 gm sugar So, Present rate of sugar = Rs. 28 per kg. If the present value is Rs. 90, the original value = Rs. 100 If the present value is Rs. 28 the original value $= Rs . \frac{100}{90} \times 28 = Rs . 31.11$

539.

The length of a rectangle is increased by 10% and breadth decreased by 10% Then the area of the new rectangle is :

(A) Neither decreased nor increased
(B) Increased by 1%
(C) Decreased by 1%
(D) Decreased 10%

Solution: Decrease in area $\begin{aligned} = \frac{x^{2}}{100} % \\ = \frac{{(10)}^{2}}{100} \\ = 1 % \end{aligned}$

540.

The contents of a certain box consist of 14 apples and 23 oranges. How many oranges must be removed from the box so that 70% of the pieces of fruit in the box will be apples ?

(A) 6
(B) 12
(C) 17
(D) 36

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Practice MCQ Questions and Answer on Percentage

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