Practice MCQ Questions and Answer on Percentage

511.

Find the value : 3.2% of 500 ÃÂÃÂÃÂÃÂÃÂÃÂ 2.4% of ? = 288

(A) 600
(B) 650
(C) 700
(D) 750

Solution: Let 3.2% of 500 × 2.4% of x = 288 Then, $\Rightarrow (\frac{32}{10} \times \frac{1}{100} \times 500) \times$ $(\frac{24}{10} \times \frac{1}{100} \times x)$ $= 288$ $\begin{aligned} \Rightarrow 16 \times \frac{3 x}{125} = 288 \\ \Rightarrow x = \frac{288 \times 125}{16 \times 3} \\ \Rightarrow x = 750 \end{aligned}$

512.

Vinay decided to donate 5% of his salary. On the day of donation he changed his mind and donated Rs. 1687.50, which was 75% of what he had decided earlier. How much is Vinay's salary ?

(A) Rs. 33750
(B) Rs. 37500
(C) Rs. 45000
(D) Cannot be determined

Solution: Let Vinay's salary be Rs. $x$ Then, 75% of 5% of $x$ = 1687.50 ⇒ $\frac{75}{100}$ × $\frac{5}{100}$ × $x$ = 1687.50 ⇒ $x$ = $(\frac{1687.50 \times 100 \times 100}{75 \times 5})$ ⇒ $x$ = 45000

513.

At an election there were two candidate got 38% of votes and lost by 7200 votes. The total numbers of valid votes were :

(A) 13000
(B) 13800
(C) 16200
(D) 30000

514.

The cost of a car is 400% greater than the cost of a bike. If there is an increase in the cost of the car is 15% and that of bike 20%. Then the total increase in the cost of the 5 cars and 10 bikes is:

(A) 17.5%
(B) $16 \frac{3}{7}$ %
(C) 18.5%
(D) 18.25%

Solution: Let the bike's initial cost be x and then car's initial cost be 5x After the increase, Bike price = 1.2x Car price = 5.75x Initial total cost of 5 cars and 10 bikes, = 25x + 10x = 35x New cost, = 28.75x + 12x = 40.75x Change in cost = (40.75x - 35x) = 5.75x % change = $\frac{5.75 x \times 100}{35} = 16 \frac{3}{7} %$

515.

When income tax is 3 paise in a rupee, a person's net income is Rs. 237650. What will it be when the income tax is raised to 7 paise ?

(A) Rs. 233000
(B) Rs. 231650
(C) Rs. 227850
(D) None of these

Solution: Let the person's gross income be Rs. $x$ Then, ⇒ (100 - 3)% of $x$ = 237650 ⇒ 97% of $x$ = 237650 ⇒ $\frac{97 x}{100}$ = 237650 ⇒ $x$ = $(\frac{237650 \times 100}{97})$ ⇒ $x$ = 245000 ∴ When income tax is raised to 7%, we have : Net income : = (100 - 7)% of Rs. 245000 = 93% of Rs. 245000 = Rs. $(\frac{93}{100} \times 245000)$ = Rs. 227850

516.

In a town, the population was 8000. In one year, male population increased by 10% and female population increased by 8% but the total population increased by 9%. The number of males in the town was :

(A) 4000
(B) 4500
(C) 5000
(D) 6000

Solution: Note :In such type of questions use allegation method to save your valuable time. Required number of males = $\frac{8000}{(1 + 1)}$ × 1 = 4000

517.

A candidate who gets 20% marks in a examination fails by 30 marks but another candidate who gets 32% gets 42 marks more than the pass marks. Then the percentage of pass marks is :

(A) 52%
(B) 50%
(C) 33%
(D) 25%

Solution: Let the maximum marks = x According to the question, Case (i) pass marks = $\frac{20 x}{100}$ + 30 Case (ii) pass marks = $\frac{32 x}{100}$ - 42 Note : Pass marks would be same in both cases. $\frac{20 x}{100}$ + 30 = $\frac{32 x}{100}$ - 42 $\frac{12 x}{100}$ = 72 x = 600 Pass marks : = 600 × $\frac{20}{100}$ + 30 = 150 Required percentage : = $\frac{150}{600}$ × 100 = 25%

518.

The average weight of a class of students is 67.5 kg. The weight of the class teacher is 25% more than the average weight of the class. The average weight of the class is less than the class teacher by x%. The value of x is:

(A) 33.335
(B) 25%
(C) 20%
(D) 22%

Solution: 100 == 25% ↑ ==> 125 == x%↓ ==> 100 $x % = \frac{25 \times 100}{100} = 25 %$ We don't need the actual value to calculate the answer

519.

If decreasing 110 by x% gives the same result as increasing 50 by x%, then x% of 650 is what percentage (correct to the nearest integer) more than (x - 10)% of 780?

(A) 17%
(B) 12%
(C) 18%
(D) 14%

Solution: $\begin{aligned} 110 \times \frac{(100 - x)}{100} = 50 \times \frac{(100 + x)}{100} \\ 11 (100 - x) = 5 (100 + x) \\ 1100 - 11 x = 500 + 5 x \\ 16 x = 600 \\ x = \frac{800}{16} = \frac{75}{2} = 37 \frac{1}{2} % \\ Now, \\ 650 \times \frac{75}{200} \to 780 \times \frac{55}{200} \\ \frac{25}{2} \to 11 \\ 25 \to 22 \\ = \frac{3}{22} \times 100 = 14 % \end{aligned}$

520.

In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1600 employees, then the no. of female employees who are computer literate ?

(A) 690
(B) 674
(C) 672
(D) 960

Solution: Total employees = 1600 Female employees, 60% of 1600 $= \frac{60 \times 1600}{100} = 960$ Then male employees = 640 50% of male are computer literate, = 320 male computer literate 62% of total employees are computer literate, $= \frac{62 \times 1600}{100} = 992$ computer literate Thus, Female computer literate = 992 - 320 = 672 Alternatively : Let 60% employees are female and 40% are male Then, 20% of male are computer literate and 42% are female computer literate Female computer literate $= \frac{1600 \times 42}{100} = 672$

«
1
2
...
49
50
51
52
53
54
55
56
57
58
Next ›
Last »

Indian Polity Mcq IAS GK Question India GK World GK GK questions GK Quiz Biology GK Science GK Physics GK Chemistry GK General Awareness Computer GK Political GK Indian Political GK Economics GK History GK Sports GK Geography GK Teaching Aptitude GK CTET/TET GK B Ed Entrance GK Banking GK SSC GK UPSC GK Indian Army GK Hindi Grammar GK Hindi Grammar MCQ Reasoning questions Bihar GK Rajasthan GK Jharkhand GK MP GK UP GK Chhattisgarh GK Haryana GK HP GK Maharashtra GK Electronics GK Agriculture GK States/Capitals GK Books Name & Author Arthimetic Verbal Reasoning Non Verbal Reasoning English

Practice MCQ Questions and Answer on Percentage

General Knowledge