Practice MCQ Questions and Answer on Triangles

131.

In an isosceles triangle ÃÂÃÂÃÂÃÂÃÂÃÂABC, AB = AC and ÃÂÃÂÃÂÃÂ¢ÃÂÃÂÃÂÃÂÃÂÃÂ A = 80ÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°. The bisector of ÃÂÃÂÃÂÃÂ¢ÃÂÃÂÃÂÃÂÃÂÃÂ B and ÃÂÃÂÃÂÃÂ¢ÃÂÃÂÃÂÃÂÃÂÃÂ C meet at D. The ÃÂÃÂÃÂÃÂ¢ÃÂÃÂÃÂÃÂÃÂÃÂ BDC is equal to.

(A) 90°
(B) 100°
(C) 130°
(D) 80°

Solution: ∵ AB = AC Point D is the incenter ∴ ∠BDC = 90° + $\frac{1}{2}$ ∠A = 90° + $\frac{1}{2}$ × 80° = 90° + 40° = 130°

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Practice MCQ Questions and Answer on Triangles

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